Locate current directory in a script

Edgardo_Morales · December 8, 2021, 10:45pm

Hello, I’m working on a script that takes an open file, copies some of its contents into a new file, and then saves this new file into the same directory as the old file.

I’ve gotten those 2 first things to work, but I’m having difficulty with that last one thing, mainly because I can’t find a function in the documentation that can return the folder of a specific file.

I’ve spent a really long time reading the documentation and I probably just missed it, so I would appreciate some help.

Thanks a lot!

LuxTK · December 9, 2021, 2:52am

If you know the open or active sprite’s filename (full path + filename with extension) you can use this

github.com

aseprite/api/blob/main/api/app_fs.md#appfsfilepath

# app.fs

A set of function to handle file names and the file system.

# Path & File Name Manipulation

## app.fs.pathSeparator

```lua
local fn = "path" .. app.fs.pathSeparator .. "filename.png"
```

Returns the preferred path separator of the current platform, it is
`/` on macOS and Linux, and `\` on Windows. Preferably you should use
[app.fs.joinPath()](#appfsjoinpath).

Example:

```lua
local sep = app.fs.pathSeparator

This file has been truncated. show original

For example:

print(app.fs.filePath(app.activeSprite.filename))

will print the active sprite’s path.

And you can pass any path to that function. It doesn’t have to be aseprite supported/specific files (like a png).

Edgardo_Morales · December 9, 2021, 5:30pm

Thank you! This is exactly what I needed.